package brotli import "math" /* Copyright 2013 Google Inc. All Rights Reserved. Distributed under MIT license. See file LICENSE for detail or copy at https://opensource.org/licenses/MIT */ /* Computes the bit cost reduction by combining out[idx1] and out[idx2] and if it is below a threshold, stores the pair (idx1, idx2) in the *pairs queue. */ func compareAndPushToQueueLiteral(out []histogramLiteral, cluster_size []uint32, idx1 uint32, idx2 uint32, max_num_pairs uint, pairs []histogramPair, num_pairs *uint) { var is_good_pair bool = false var p histogramPair p.idx2 = 0 p.idx1 = p.idx2 p.cost_combo = 0 p.cost_diff = p.cost_combo if idx1 == idx2 { return } if idx2 < idx1 { var t uint32 = idx2 idx2 = idx1 idx1 = t } p.idx1 = idx1 p.idx2 = idx2 p.cost_diff = 0.5 * clusterCostDiff(uint(cluster_size[idx1]), uint(cluster_size[idx2])) p.cost_diff -= out[idx1].bit_cost_ p.cost_diff -= out[idx2].bit_cost_ if out[idx1].total_count_ == 0 { p.cost_combo = out[idx2].bit_cost_ is_good_pair = true } else if out[idx2].total_count_ == 0 { p.cost_combo = out[idx1].bit_cost_ is_good_pair = true } else { var threshold float64 if *num_pairs == 0 { threshold = 1e99 } else { threshold = brotli_max_double(0.0, pairs[0].cost_diff) } var combo histogramLiteral = out[idx1] var cost_combo float64 histogramAddHistogramLiteral(&combo, &out[idx2]) cost_combo = populationCostLiteral(&combo) if cost_combo < threshold-p.cost_diff { p.cost_combo = cost_combo is_good_pair = true } } if is_good_pair { p.cost_diff += p.cost_combo if *num_pairs > 0 && histogramPairIsLess(&pairs[0], &p) { /* Replace the top of the queue if needed. */ if *num_pairs < max_num_pairs { pairs[*num_pairs] = pairs[0] (*num_pairs)++ } pairs[0] = p } else if *num_pairs < max_num_pairs { pairs[*num_pairs] = p (*num_pairs)++ } } } func histogramCombineLiteral(out []histogramLiteral, cluster_size []uint32, symbols []uint32, clusters []uint32, pairs []histogramPair, num_clusters uint, symbols_size uint, max_clusters uint, max_num_pairs uint) uint { var cost_diff_threshold float64 = 0.0 var min_cluster_size uint = 1 var num_pairs uint = 0 { /* We maintain a vector of histogram pairs, with the property that the pair with the maximum bit cost reduction is the first. */ var idx1 uint for idx1 = 0; idx1 < num_clusters; idx1++ { var idx2 uint for idx2 = idx1 + 1; idx2 < num_clusters; idx2++ { compareAndPushToQueueLiteral(out, cluster_size, clusters[idx1], clusters[idx2], max_num_pairs, pairs[0:], &num_pairs) } } } for num_clusters > min_cluster_size { var best_idx1 uint32 var best_idx2 uint32 var i uint if pairs[0].cost_diff >= cost_diff_threshold { cost_diff_threshold = 1e99 min_cluster_size = max_clusters continue } /* Take the best pair from the top of heap. */ best_idx1 = pairs[0].idx1 best_idx2 = pairs[0].idx2 histogramAddHistogramLiteral(&out[best_idx1], &out[best_idx2]) out[best_idx1].bit_cost_ = pairs[0].cost_combo cluster_size[best_idx1] += cluster_size[best_idx2] for i = 0; i < symbols_size; i++ { if symbols[i] == best_idx2 { symbols[i] = best_idx1 } } for i = 0; i < num_clusters; i++ { if clusters[i] == best_idx2 { copy(clusters[i:], clusters[i+1:][:num_clusters-i-1]) break } } num_clusters-- { /* Remove pairs intersecting the just combined best pair. */ var copy_to_idx uint = 0 for i = 0; i < num_pairs; i++ { var p *histogramPair = &pairs[i] if p.idx1 == best_idx1 || p.idx2 == best_idx1 || p.idx1 == best_idx2 || p.idx2 == best_idx2 { /* Remove invalid pair from the queue. */ continue } if histogramPairIsLess(&pairs[0], p) { /* Replace the top of the queue if needed. */ var front histogramPair = pairs[0] pairs[0] = *p pairs[copy_to_idx] = front } else { pairs[copy_to_idx] = *p } copy_to_idx++ } num_pairs = copy_to_idx } /* Push new pairs formed with the combined histogram to the heap. */ for i = 0; i < num_clusters; i++ { compareAndPushToQueueLiteral(out, cluster_size, best_idx1, clusters[i], max_num_pairs, pairs[0:], &num_pairs) } } return num_clusters } /* What is the bit cost of moving histogram from cur_symbol to candidate. */ func histogramBitCostDistanceLiteral(histogram *histogramLiteral, candidate *histogramLiteral) float64 { if histogram.total_count_ == 0 { return 0.0 } else { var tmp histogramLiteral = *histogram histogramAddHistogramLiteral(&tmp, candidate) return populationCostLiteral(&tmp) - candidate.bit_cost_ } } /* Find the best 'out' histogram for each of the 'in' histograms. When called, clusters[0..num_clusters) contains the unique values from symbols[0..in_size), but this property is not preserved in this function. Note: we assume that out[]->bit_cost_ is already up-to-date. */ func histogramRemapLiteral(in []histogramLiteral, in_size uint, clusters []uint32, num_clusters uint, out []histogramLiteral, symbols []uint32) { var i uint for i = 0; i < in_size; i++ { var best_out uint32 if i == 0 { best_out = symbols[0] } else { best_out = symbols[i-1] } var best_bits float64 = histogramBitCostDistanceLiteral(&in[i], &out[best_out]) var j uint for j = 0; j < num_clusters; j++ { var cur_bits float64 = histogramBitCostDistanceLiteral(&in[i], &out[clusters[j]]) if cur_bits < best_bits { best_bits = cur_bits best_out = clusters[j] } } symbols[i] = best_out } /* Recompute each out based on raw and symbols. */ for i = 0; i < num_clusters; i++ { histogramClearLiteral(&out[clusters[i]]) } for i = 0; i < in_size; i++ { histogramAddHistogramLiteral(&out[symbols[i]], &in[i]) } } /* Reorders elements of the out[0..length) array and changes values in symbols[0..length) array in the following way: * when called, symbols[] contains indexes into out[], and has N unique values (possibly N < length) * on return, symbols'[i] = f(symbols[i]) and out'[symbols'[i]] = out[symbols[i]], for each 0 <= i < length, where f is a bijection between the range of symbols[] and [0..N), and the first occurrences of values in symbols'[i] come in consecutive increasing order. Returns N, the number of unique values in symbols[]. */ var histogramReindexLiteral_kInvalidIndex uint32 = math.MaxUint32 func histogramReindexLiteral(out []histogramLiteral, symbols []uint32, length uint) uint { var new_index []uint32 = make([]uint32, length) var next_index uint32 var tmp []histogramLiteral var i uint for i = 0; i < length; i++ { new_index[i] = histogramReindexLiteral_kInvalidIndex } next_index = 0 for i = 0; i < length; i++ { if new_index[symbols[i]] == histogramReindexLiteral_kInvalidIndex { new_index[symbols[i]] = next_index next_index++ } } /* TODO: by using idea of "cycle-sort" we can avoid allocation of tmp and reduce the number of copying by the factor of 2. */ tmp = make([]histogramLiteral, next_index) next_index = 0 for i = 0; i < length; i++ { if new_index[symbols[i]] == next_index { tmp[next_index] = out[symbols[i]] next_index++ } symbols[i] = new_index[symbols[i]] } new_index = nil for i = 0; uint32(i) < next_index; i++ { out[i] = tmp[i] } tmp = nil return uint(next_index) } func clusterHistogramsLiteral(in []histogramLiteral, in_size uint, max_histograms uint, out []histogramLiteral, out_size *uint, histogram_symbols []uint32) { var cluster_size []uint32 = make([]uint32, in_size) var clusters []uint32 = make([]uint32, in_size) var num_clusters uint = 0 var max_input_histograms uint = 64 var pairs_capacity uint = max_input_histograms * max_input_histograms / 2 var pairs []histogramPair = make([]histogramPair, (pairs_capacity + 1)) var i uint /* For the first pass of clustering, we allow all pairs. */ for i = 0; i < in_size; i++ { cluster_size[i] = 1 } for i = 0; i < in_size; i++ { out[i] = in[i] out[i].bit_cost_ = populationCostLiteral(&in[i]) histogram_symbols[i] = uint32(i) } for i = 0; i < in_size; i += max_input_histograms { var num_to_combine uint = brotli_min_size_t(in_size-i, max_input_histograms) var num_new_clusters uint var j uint for j = 0; j < num_to_combine; j++ { clusters[num_clusters+j] = uint32(i + j) } num_new_clusters = histogramCombineLiteral(out, cluster_size, histogram_symbols[i:], clusters[num_clusters:], pairs, num_to_combine, num_to_combine, max_histograms, pairs_capacity) num_clusters += num_new_clusters } { /* For the second pass, we limit the total number of histogram pairs. After this limit is reached, we only keep searching for the best pair. */ var max_num_pairs uint = brotli_min_size_t(64*num_clusters, (num_clusters/2)*num_clusters) if pairs_capacity < (max_num_pairs + 1) { var _new_size uint if pairs_capacity == 0 { _new_size = max_num_pairs + 1 } else { _new_size = pairs_capacity } var new_array []histogramPair for _new_size < (max_num_pairs + 1) { _new_size *= 2 } new_array = make([]histogramPair, _new_size) if pairs_capacity != 0 { copy(new_array, pairs[:pairs_capacity]) } pairs = new_array pairs_capacity = _new_size } /* Collapse similar histograms. */ num_clusters = histogramCombineLiteral(out, cluster_size, histogram_symbols, clusters, pairs, num_clusters, in_size, max_histograms, max_num_pairs) } pairs = nil cluster_size = nil /* Find the optimal map from original histograms to the final ones. */ histogramRemapLiteral(in, in_size, clusters, num_clusters, out, histogram_symbols) clusters = nil /* Convert the context map to a canonical form. */ *out_size = histogramReindexLiteral(out, histogram_symbols, in_size) }